Question

The point-slope form of the equation of of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x - 12). What

is the standard form of the equation for this line?
O x- 4y = 8
O x-4y=2
O 4x-y= 8
O 4x-y=2

Answer 1

Answer:
`(1)/(4)`x - y = 2

Explanation:

Standard form is Ax + By = C where A, B, and C, are integers.

Given:

y - 1 = 1/4(x - 12)

Distribute:

y - 1 =
`(1)/(4)`x - 3

Add 3 to both sides of the equation:

y + 2 =
`(1)/(4)`x

Subtract y from both sides of the equation:

2 =
`(1)/(4)`x - y

Apply the reflexive property:

`(1)/(4)`x - y = 2