5.3k views
2 votes
The point-slope form of the equation of of the line that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x - 12). What

is the standard form of the equation for this line?
O x- 4y = 8
O x-4y=2
O 4x-y= 8
O 4x-y=2

1 Answer

4 votes

Answer:
(1)/(4)x - y = 2

Explanation:

Standard form is Ax + By = C where A, B, and C, are integers.

Given:

y - 1 = 1/4(x - 12)

Distribute:

y - 1 =
(1)/(4)x - 3

Add 3 to both sides of the equation:

y + 2 =
(1)/(4)x

Subtract y from both sides of the equation:

2 =
(1)/(4)x - y

Apply the reflexive property:


(1)/(4)x - y = 2

User Vaaljan
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories