Question

What is the solution to this system of equations? (I suggest using the elimination method by multiplying the first equation by 3.) 2x + y = 20 6x - 5y = -4 Points earned for putting your solution as an ordered pair. If work is shown, partial credit can be earned. Question 3 options:

Answer 1

(6,8)

Explanation:

2x + y = 20 (1)

6x - 5y = -4 (2)

Multiplying EQ 1 by 5

=> 5(2x + y) = 5(20)

=> 10x + 5y = 100 (3)

On adding 2 and 3

=> 6x - 5y + 10x + 5y = -4 + 100

=> 16x = 96

=> x = 96/16

=> x = 6

From 1

=> 2(6) + y = 20

=> 12 + y = 20

=> y = 20 - 12

=> y = 8

In pair

(x,y) = (6,8)

Answer 2

(6,8)

Explanation:

2x + y = 20

6x - 5y = -4

Multiply the first equation by -3

-3(2x + y) = -3*20

-6x -3y = -60

Add this to the second equation

-6x-3y = -60

6x - 5y = -4

--------------------

-8y = -64

Divide each side by -8

-8y/-8 = -64/-8

y = 8

Now find x

2x+y = 20

2x +8 = 20

2x+8-8 = 20-8

2x = 12

Divide by 2

2x/2 = 12/2

x = 6

(6,8)