Question

Solve the system: 2x+3y=6 and x=-2y+3. I need help

Answer 1

`\large\boxed{x=3,\ y=0\to(3,\ 0)}`

Explanation:

`\left\{\begin{array}{ccc}2x+3y=6&(1)\\x=-2y+3&(2)\end{array}\right\\\\\text{Substitute (2) to (1):}\\\\2(-2y+3)+3y=6\qquad\text{use distributive property}\\\\(2)(-2y)+(2)(3)+3y=6\\\\-4y+6+3y=6\qquad\text{subtract 6 from both sides}\\\\-y=0\to\boxed{y=0}\\\\\text{Put the value of y to (2):}\\\\x=-2(0)+3\\\\x=0+3\\\\\boxed{x=3}`