Question

CAN SOMEONE PLEASE SHOW WORK FOR THESE PROBLEMS WILL GIVE BAINLIEST!!!!!!!!!EMERGENCY

Answer 1

Part 1)
`x\geq10`

Part 2)
`m\leq -9`

Part 3)
`p\geq 5`

Part 4)
`x<-10`

Part 5)
`b<-10`

Part 6)
`n<5`

Part 7)
`n <6`

Part 8)
`r\leq 4`

Part 9)
`x\geq 7`

Part 10)
`p\leq 0`

Part 11)
`x<1`

Part 12)
`a > 24`

Explanation:

Part 1)
`2x+4\geq24`

Subtract 4 both sides

`2x\geq24-4`

`2x\geq20`

Divide by 2 both sides

`x\geq10`

the solution is the interval ------> [10,∞)

The solution is the shaded area to the right of the solid line at number 10 (closed circle).

see the attached figure

Part 2)
`(m)/(3)-3\leq -6`

Adds 3 both sides

`(m)/(3)\leq -6+3`

`(m)/(3)\leq -3`

Multiply by 3 both sides

`m\leq -9`

the solution is the interval ------> (-∞,-9]

The solution is the shaded area to the left of the solid line at number -9 (closed circle).

see the attached figure

Part 3)
`-3(p+1)\leq -18`

applying the distributive property left side

`-3p-3\leq -18`

adds 3 both sides

`-3p\leq -18+3`

`-3p\leq -15`

Multiply by -1 both sides

`3p\geq 15`

Divide by 3 both sides

`p\geq 5`

the solution is the interval ------> [5,∞)

The solution is the shaded area to the right of the solid line at number 5 (closed circle).

see the attached figure

Part 4)
`-4(-4+x)>56`

applying the distributive property left side

`16-4x>56`

Subtract 16 both sides

`-4x>56-16`

`-4x>40`

Multiply by -1 both sides

`4x<-40`

Divide by 4 both sides

`x<-10`

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

see the attached figure

Part 5)
`-b-2>8`

adds 2 both sides

`-b>8+2`

`-b>10`

Multiply by -1 both sides

`b<-10`

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

Part 6)
`-4(3+n)>-32`

applying the distributive property left side

`-12-4n>-32`

adds 12 both sides

`-4n>-32+12`

`-4n>-20`

multiply by -1 both sides

`4n<20`

divide by 4 both sides

`n<5`

the solution is the interval ------> (-∞,5)

The solution is the shaded area to the left of the dashed line at number 5 (open circle).

see the attached figure

Part 7)
`4+(n)/(3) <6`

Subtract 4 both sides

`(n)/(3) <6-4`

`(n)/(3) <2`

Multiply by 3 both sides

`n <6`

the solution is the interval ------> (-∞,6)

The solution is the shaded area to the left of the dashed line at number 6 (open circle).

see the attached figure

Part 8)
`-3(r-4)\geq 0`

applying the distributive property left side

`-3r+12\geq 0`

subtract 12 both sides

`-3r\geq -12`

divide by -1 both sides

`3r\leq 12`

divide by 3 both sides

`r\leq 4`

the solution is the interval ------> (-∞,4]

The solution is the shaded area to the left of the solid line at number 4 (closed circle).

see the attached figure

Part 9)
`-7x-7\leq -56`

Adds 7 both sides

`-7x\leq -56+7`

`-7x\leq -49`

Multiply by -1 both sides

`7x\geq 49`

Divide by 7 both sides

`x\geq 7`

the solution is the interval ------> [7,∞)

The solution is the shaded area to the right of the solid line at number 7 (closed circle).

see the attached figure

Part 10)
`-3(p-7)\geq 21`

applying the distributive property left side

`-3p+21\geq 21`

subtract 21 both sides

`-3p\geq 21-21`

`-3p\geq 0`

Multiply by -1 both sides

`3p\leq 0`

`p\leq 0`

the solution is the interval ------> (-∞,0]

The solution is the shaded area to the left of the solid line at number 0 (closed circle).

see the attached figure

Part 11)
`-11x-4> -15`

Adds 4 both sides

`-11x> -15+4`

`-11x> -11`

Multiply by -1 both sides

`11x<11`

Divide by 11 both sides

`x<1`

the solution is the interval ------> (-∞,1)

The solution is the shaded area to the left of the dashed line at number 1 (open circle).

see the attached figure

Part 12)
`(-9+a)/(15)>1`

Multiply by 15 both sides

`-9+a > 15`

Adds 9 both sides

`a > 15+9`

`a > 24`

the solution is the interval ------> (24,∞)

The solution is the shaded area to the right of the dashed line at number 24 (open circle).

see the attached figure