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100 POINTS!!! To find the distance AB across a river, a distance BC of 319 m is laid off on one side of the river. It is found that B = 104.6° and C = 14.4°. Find AB.

User Kalani
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1 Answer

5 votes
5 votes

Answer: AB = 90.7 meter

Given following:

  • BC = 319 meter
  • angle B = 104.6°
  • angle C = 14.4°

Find angle A :

⇒ 180° - (104.6° + 14.4°)

⇒ 61°

Now, use sine rule:


\sf (AB)/(BC) = (sin(C^(\circ )))/(sin(A^(\circ \:)))


\sf (AB)/(319) = \frac{sin(14.4) } {sin(61)}


\sf AB = \frac{319 \ sin(14.4) } {sin(61)}


\sf AB = 90.70464953 \quad \approx \quad 90.7 \ m \ (rounded \: to \: nearest \ tenth)

100 POINTS!!! To find the distance AB across a river, a distance BC of 319 m is laid-example-1
User Anaderi
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