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A 320 HZ tuning fork is resonating in a closed tube on a day when the speed of sound is 335 m/s. what is the length of the closed tube?

0.26 m
0.24 m
0.96 m
1.05 m

2 Answers

6 votes

v=fλ

λ= 335 m/s/320 Hz= 1.05 m

User Timoteo
by
9.2k points
4 votes

Answer: The length of the closed tube is 1.05 m

Step-by-step explanation:

Wave speed is defined as the product of its wavelength and frequency.

Mathematically,


\text{Wave speed}=\lambda* \\u

where,


\lambda = length of the closed tube = ?


\\u = frequency of the tuning fork = 320 Hz =
320s^(-1)

Speed of the sound wave = 335 m/s

Putting values in above equation, we get:


335m/s=\lambda* 320s^(-1)\\\\\lambda=(335m/s)/(320s^(-1))=1.05m

Hence, the length of the closed tube is 1.05 m

User Prelite
by
8.2k points