Answer:
The area of the larger rectangle is
![108\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/esnczkcejr4wf4sfud5oz70auc51sefabc.png)
Explanation:
we know that
If two figures are similar then the ratio of its areas is equal to the scale factor squared
and the ratio of its corresponding sides is equal to the scale factor
Let
z-----> the scale factor
x-----> the area of small rectangle
y-----> the area of larger rectangle
so
![z^(2) =(x)/(y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/7vpkb0kxlh0u3erblhl708unom5fiidxv3.png)
we have
![z=2/6](https://img.qammunity.org/2020/formulas/mathematics/high-school/ut7m7anawdqar2zgff55k6ngl6mo4g3cb6.png)
![x=12\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/xxq40ms0lgfz7os6s60cc9wabhqbt1goyc.png)
substitute and solve for y
![(2/6)^(2) =(12)/(y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/tki6btad52q5iuixcp45ncsp5hn92qxn9z.png)
![y=12/(4/36)=108\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/j2u80ntorox8vvgscmfk8bydp4byu9wmjq.png)