Question

What are the zeros of the polynomial function? f(x)=x2−16x+48 Enter your answers in the boxes.

Answer 1

4 and 12

Explanation:

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Answer 2

`x_(1,2)=4,\ 12`

Explanation:

Consider the polynmial function
`f(x)=x^2-16x+48.` The zeros of the polynomial function are the values of x at which f(x)=0. Solve the equation
`x^2-16x+48=0:`

`D=b^2-4ac=(-16)^2-4\cdot 1\cdot 48=256-192=64=8^2,\\ \\x_(1,2)=(-b\pm √(D))/(2a)=(-(-16)\pm √(64))/(2\cdot 1)=(16\pm 8)/(2)=4,\ 12.`