Question

You have an office building that is 600 square feet in area. What are two possible dimensions how your office could be constructed?

Answer 1

`20\ ft` by
`30\ ft`

`15\ ft` by
`40\ ft`

Explanation:

In this problem I'm assuming the office is rectangular.

so

The area of rectangle is equal to

`A=LW`

where

L is the length of the rectangle

W is the width of the rectangle

In this problem we have

`A=600\ ft^(2)`

so

`600=LW` ------> equation A

Find two possible dimensions of the office

case A) Assume a length side L and find the value of W in the equation A

so

For
`L=30\ ft`

substitute in the equation and solve for W

`600=(30)W`

`W=600/30=20\ ft`

The dimensions are
`20\ ft` by
`30\ ft`

case B) Assume a length side L and find the value of W in the equation A

so

For
`L=40\ ft`

substitute in the equation and solve for W

`600=(40)W`

`W=600/40=15\ ft`

The dimensions are
`15\ ft` by
`40\ ft`