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You have an office building that is 600 square feet in area. What are two possible dimensions how your office could be constructed?

User Rpadovani
by
7.6k points

1 Answer

2 votes

Answer:


20\ ft by
30\ ft


15\ ft by
40\ ft

Explanation:

In this problem I'm assuming the office is rectangular.

so

The area of rectangle is equal to


A=LW

where

L is the length of the rectangle

W is the width of the rectangle

In this problem we have


A=600\ ft^(2)

so


600=LW ------> equation A

Find two possible dimensions of the office

case A) Assume a length side L and find the value of W in the equation A

so

For
L=30\ ft

substitute in the equation and solve for W


600=(30)W


W=600/30=20\ ft

The dimensions are
20\ ft by
30\ ft

case B) Assume a length side L and find the value of W in the equation A

so

For
L=40\ ft

substitute in the equation and solve for W


600=(40)W


W=600/40=15\ ft

The dimensions are
15\ ft by
40\ ft

User Unome
by
8.5k points

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