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Prove the divisibility of the following numbers:

1. 25^7+5^13 by 30
2. 7^6+7^5−7^4 by 11
3. 5^5−5^4+5^3 by 7

1 Answer

6 votes

1. Make use of prime factorizations:


25^7+5^(13)=(5^2)^7+5^(13)=5^(14)+5^(13)

Pull out a common factor of
5^(13):


5^(14)+5^(13)=5^(13)(5+1)=5^(13)\cdot6

Since
30=5\cdot 6, it follows that
30\mid25^7+5^(13).

2. Pull out a common factor of
7^4:


7^6+7^5-7^4=7^4(7^2+7-1)=7^4\cdot55=5\cdot7^4\cdot11

3. Pull out a common factor of
5^3:


5^5-5^4+5^3=5^3(5^2-5+1)=5^3\cdot21=3\cdot5^3\cdot7

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