Answer:
It cooled 58.4 degrees
Explanation:
T(t) = 68 + 144e ^(-.052t)
We want to find the value when t= 10
T(10) = 68 + 144e ^(-.052*10)
= 68 +85.611
T(10) =153.611
We also need to know
T(0)= 68 + 144e ^(-.052*0)
=68+144
=212
We want to know how much it cools
That would be the temperature at time 0 minus the temperature at time 10
T(0) - T (10)
212-153.611
58.389
To the nearest tenth
58.4 degrees