Question

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball on her second try than her first? Express your answer in feet and inches A. 9 ft 1/2 in. B. 28 ft 1/2 in. C. 28 ft 6 in. D. 126 ft.

Answer 1

28 feet farther than 1st ball.

Explanation:

We have been given that Susan threw a softball 42 yards on her first try and
`51(1)/(3)` yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from
`51(1)/(3)` yards.

`\text{The second ball is farther from 1st ball}=51(1)/(3)\text{ yards}-42\text{ yards}`

`\text{The second ball is farther from 1st ball}=(154)/(3)\text{ yards}-42\text{ yards}`

Let us have a common denominator.

`\text{The second ball is farther from 1st ball}=(154)/(3)\text{ yards}-(42*3)/(3)\text{ yards}`

`\text{The second ball is farther from 1st ball}=(154)/(3)\text{ yards}-(126)/(3)\text{ yards}`

`\text{The second ball is farther from 1st ball}=(154-126)/(3)\text{ yards}`

`\text{The second ball is farther from 1st ball}=(28)/(3)\text{ yards}`

`\text{1 yard}=3\text{ feet}`

`(28)/(3)\text{ yards}=(28)/(3)* 3\text{ feet}`

`(28)/(3)\text{ yards}=28\text{ feet}`

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.