Question

Iron crystallizes in a body-centered cubic cell having an edge length of 287 pm. What is the density of iron in g/cm3.

Answer 1

Answer:The density of iron in
`0.0784 g/cm^3`

Step-by-step explanation:

The density of the crystal solids is calculated by using :

`\rho=(Z* M)/(N_A* a^3)`

Z = number of atoms in crystal lattice in body centered cubic cell = 2

M = Atomic mass = 55.85 g/mol

a = Edge length of the crystal = 287 pm =
`287* 10^(-10)cm`

`1 pm=1* 1-^(-10) cm`

`\rho=(2* 55.85 g/mol)/(6.022* 10^(23)* (287* 10^(-10)cm)^3)`

`\rho=0.0784 g/cm^3`

The density of iron in
`0.0784 g/cm^3`