Question

Arrange the distances between Earth and various celestial objects in order from least to greatest. Use the conversion table to help you. 1 AU 1.5 × 108 km 1 ly 63,000 AU 1 pc 3.262 ly distance to the star Betelgeuse: 640 ly distance to the star VY Canis Majoris: 3.09 × 108 AU distance to the galaxy Large Magellanic Cloud: 49976 pc distance to Neptune at the farthest: 4.7 billion km ↓ ↓ ↓

Answer 1

distance to the star Betelgeuse: 640 ly

As we know that

`1 ly = 63000 AU`

also we know that

`1AU = 1.5 * 10^8 km`

`1 ly = 63000 (1.5 * 10^8) = 9.45 * 10^(12) km`

So the distance of Betelgeuse = 640 ly

`d_1 = 640 * 9.45 * 10^(12) = 6.05 * 10^(15) m`

distance to the star VY Canis Majoris:
`3.09 × 10^8 AU`

`d_2 = 3.09* 10^8 * 1.5 * 10^8 km`

`d_2 = 4.64 * 10^(16) km`

distance to the galaxy Large Magellanic Cloud: 49976 pc

`1 pc = 3.262 ly = 3.262 * 9.45 * 10^(12) km`

`1pc = 3.08 * 10^(13) km`

now we have

`d_3 = 49976 * 3.08 * 10^(13)`

`d_3 = 1.54 * 10^(18) km`

distance to Neptune at the farthest: 4.7 billion km

`d_4 = 4.7 * 10^9 km`

now the order of distance from least to greatest is as following

1. distance to Neptune at the farthest

2. distance of Betelgeuse

3. distance to the star VY Canis Majoris

4. distance to the galaxy Large Magellanic Cloud