Answer: Option A is correct!
Explanation:
h(x) =
![\sqrt[3]{125-x}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t32shpamgvl98pix1a61yvo7ms05ptabgh.png)
Plugging x =342 in h(x) ,we get
![\sqrt[3]{125-342}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d848mnrcc3j1viaq6ytcnaj1gy32ivcuio.png)
![\sqrt[3]{-217}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lba34gtg71wtlh3grqvaew4nzs4jphsk2z.png)
Which is not equal to -6
Therefore Option A does not lie on the given graph h(x) .
For option B ,we plug x = 117 in h(x)
h(x) =
![\sqrt[3]{125-117}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lcvbcq74ejex50weddmf2qfobhtarh3fvy.png)
=
![\sqrt[3]{8}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y4x5uilt4tpgxv0sye1kfzzfpj8fz2fgnv.png)
= 2
Therefore option B lies on the given graph of h(x) =
![\sqrt[3]{125-x}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t32shpamgvl98pix1a61yvo7ms05ptabgh.png)
similarly We can show that C and D also lies on the graph
So optionA is our answer.