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1) The dimensions of an irregular solid are as shown in the figure below.

a) Write a polynomial function, in standard form, to model the volume of this solid.

b) If the volume of the solid is 208 cubic inches, what is the value of x?

1) The dimensions of an irregular solid are as shown in the figure below. a) Write-example-1
User Robert Conn
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1 Answer

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Hello,

a) Volume of the figure = Volume of light blue rectangular parallelepiped - volume of dark blue rectangular parallelepiped

Volume of rectangular parallelepiped = lengh × high × height

Volume of light blue rectangular parallelepiped :

V = (x + 2) × (x + 5) × (2x + 1)

V = (x² + 5x + 2x + 10) × (2x + 1)

V = (x² + 7x + 10) × (2x + 1)

V = 2x³ + 15x² + 27x + 10

Volume of dark blue rectangular parallelepiped :

V = x × 3 × (x + 5)

V = 3x(x + 5)

V = 3x² + 15x

Polynomial function, in standard form, to model the volume of this solid :

V = 2x³ + 15x² + 27x + 10 - (3x² + 15x)

V = 2x³ + 15x² - 3x² + 27x - 15x + 10

V = 2x³ + 12x² + 12x + 10

b) We have to solve 2x³ + 12x² + 12x + 10 = 208

⇔ 2x³ + 12x² + 12x - 198 = 0

⇔ 2(x - 3)(x² + 9x + 33) = 0

⇔ x = 3 or x² + 9x + 33 = 0

a = 1 ; b = 9 ; c = 33

Δ = b² - 4ac = 9² - 4 × 1 × 33 = -51 < 0 ⇔ Δ < 0 ⇒ no solution

So if the volume of the solid is 208 cubic inches, the value of x is 3

User Sakana
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