Question

How to solve for ? on 2-3

Answer 1

`\large\boxed{(x+4)/(4)=(y+5)/(5)}`

`\large\boxed{(b)/(c)=(6)/(2)}`

Explanation:

`If\ (x)/(4)=(y)/(5),\ then\ (x+4)/(4)=(?)/(5)\\\\(x+4)/(4)=(x)/(4)+(4)/(4)=(x)/(4)+1\\\\\text{therefore}\\\\(x)/(4)=(y)/(5)\qquad\text{add 1 to both sides}\\\\(x)/(4)+1=(y)/(5)+1\\\\(x)/(4)+(4)/(4)=(y)/(5)+(5)/(5)\\\\(x+4)/(4)=(y+5)/(5)`

`If\ (b)/(6)=(c)/(2),\ then\ (b)/(c)=(?)/(?)\\\\(b)/(6)=(c)/(2)\qquad\text{cross multiply}\\\\2b=6c\qquad\text{divide both sides by 2}\\\\b=3c\qquad\text{divide both sides by }\ c\\eq0\\\\(b)/(c)=3\to(b)/(c)=(6)/(2)`