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A banner is made of a square and a semicircle. The square has side lengths of 24 inches. One side of the square is also the diameter of the semicircle. What is the total area of the banner? Use 3.14 for π.

User Quasar
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2 Answers

4 votes

Answer:

The total area of the banner is 802.08 in².

Explanation:

Separate the banner into simpler shapes as described in the problem: a square and a semicircle.

Find the area of the simpler figures.

Square

A = s2

A = 24 · 24

A = 576

The area of the square is 576 in2.

Semicircle

A = 1/ 2

πr2

A = 1/ 2

(3.14) (12)2

A = 1/ 2

(3.14) (144)

A = 226.08

The area of the semicircle is 226.08 in2.

Find the area of the banner.

A = 576 + 226.08

A = 802.08

The total area of the banner is 802.08 in².

User Patti
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5.8k points
1 vote
The area of the square (24in×24in) is 576.
The area of the semi-circle is 226.08 [[(r=12, pi=3.14) (A= 1/2×(pi × r^2)], r=12, r^2=144, pi=3.14, 144×3.14=452.16÷2=226.08]
The total combined area of the banner is - 802.08 in
User Jon Jaques
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6.3k points