Answer:
C) 336.
Explanation:
We have been given that the average of 5 distinct scores has the same value as the median of the 5 scores. The sum of the 5 scores is 420.
Let us find the average of our given scores.
![\text{Average}=\frac{\text{Total sum of all the numbers}}{\text{ Number of items in the set}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/npitwxpjt0psmq8v6atw17v3rbox08ot28.png)
![\text{Average score}=(420)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/bzb8hmllb4gkk5qwgm6nee9sl13asg8d7f.png)
\
![\text{Average score}=84](https://img.qammunity.org/2020/formulas/mathematics/high-school/j1bkismicq3xhjd5oyu7q8zdloa3lsudnq.png)
As median of the 5 scores is same as average of 5 scores, therefore, median of the given scores is 84.
We can find the sum of 4 scores that are not median by subtracting median score from total scores.
![\text{The sum of the 4 scores that are not median}=\text{Total scores-Median}](https://img.qammunity.org/2020/formulas/mathematics/high-school/t7hqtewrio3ams9qg99m29uzbuqg2tfugs.png)
![\text{The sum of the 4 scores that are not median}=420-84](https://img.qammunity.org/2020/formulas/mathematics/high-school/z6jd5xwrbi4qau0w81d40i0v9pgiiz095p.png)
![\text{The sum of the 4 scores that are not median}=336](https://img.qammunity.org/2020/formulas/mathematics/high-school/wca4fl51qt80xzr63qi8ncqboyfz2ugxgf.png)
Therefore, the sum of the 4 scores that are not the median is 336 and option C is the correct choice.