Register

A bag contains 3 blue and 2 green marbles. What is the probability of drawing a blue marble followed by a green marble, without replacing the first marble?

A bag contains 3 blue and 2 green marbles. What is the probability of drawing a blue marble followed by a green marble, without replacing the first marble?
229k views
1 vote
A bag contains 3 blue and 2 green marbles. What is the probability of drawing a blue marble followed by a green marble, without replacing the first marble?

User Made By FA
by
8.1k points

1 Answer

2 votes

Answer:

3/5 * 2/4 = 3/5 * 1/2 = 3/10 = 0.3 = 30%

User My Other Me
by
7.3k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!