Question

If the distance between two charged particles is increased 2.69 times, the ratio of new to old electric force is _______ times the old value. (Round your answer to two decimal places).

Answer 1

F = K Q1 Q2 / R^2 force between 2 charged partices

F2 / F1 = (R1 / R2)^2 = (1 / 2.69)^2 = .139

F2 = .139 F1