Question

What is the vertical asymptotes of the function f(x)=x-2/x*2-3x-4

Answer 1

x = -1 and x = 4

Explanation:

`f(x)=(x-2)/(x^2-3x-4)\\\\\text{DOMAIN}:\\\\x^2-3x-4\\eq0\\\\x^2-4x+x-4\\eq0\\\\x(x-4)+1(x-4)\\eq0\\\\(x-4)(x+1)\\eq0\iff x-4\\eq0\ \wedge\ x+1\\eq0\\\\x\\eq4\ \wedge\ x\\eq-1\\\\\text{Therefore the vertical asymptotes are:}\\\\x=-1\ and\ x=4.`