Question

Which function has zeros at x = -2 and x = 5?

O f(x) = x2 + 2x - 10
• f(x) = x2 - 2x - 10
O f(x) = X2 + 3x - 10
® f(x) = x2 - 3x - 10

Answer 1

f(x)=x²-3x-10

Explanation:

`f(x) = x {}^(2) - 3x - 10 \\ to \: find \: x \: intercept \:o r \: zero \: substitute \: f(x) = 0\: \\ 0 = x {}^(2) - 3x - 10 \\ x {}^(2) - 3x - 10 = 0 \\ x {}^(2) + 2x - 5x - 10 = 0 \\ x(x + 2) - 5x - 10 = 0 \\ x(x + 2) - 5(x + 2) = 0 \\ (x + 2).(x - 5) = 0 \\ x + 2 = 0 \\ x - 5 = 0 \\ x = - 2 \\ x = 5`

therefore the zeros of the equation are x₁=-2,x₂=5