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What are the relative frequencies to the nearest hundredth of the columns of the two-way table? A B Group 1 102 34 Group 2 18 14

User Ewen
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2 Answers

6 votes

Answer:

Column A: 102+18=120

Group 1:

102/120=0.85

Group 2:

18/120=0.15

Column B: 34+14=48

Group 1:

34/48=0.71

Group 2:

14/48=0.29

Hope this helps. :)

User Sheka
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5.5k points
4 votes

Answer: The relative frequencies to the nearest hundredth of the columns of the two-way table is given by :-

A B

Group 1 0.85 0.71

Group 2 0.15 0.29

Explanation:

Given two-way table : A B

Group 1 10 34

Group 2 18 14

Total data value in column A =
102+18=120

Total data value in column B =
34+14=48

Now, the relative frequency for Group 1 with column A =
(102)/(120)=0.85

The relative frequency for Group 1 with column B =
(34)/(48)=0.708333333..\approx0.71

Now, the relative frequency for Group 2 with column A =
(18)/(120)=0.15

The relative frequency for Group 2 with column B =
(14)/(48)=0.2916666666..\approx0.29

User Mxyk
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