Question

If you quadruple the temperature of a black body, by what factor will the total energy radiated per second per square meter increase? 1,024 64 16 4 256 submit answer

Answer 1

In modern physics, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T

as:

`P\alpha T^4`

where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.

then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:

`(P_(1) )/(P_(2) ) =(T_(1)^4 )/(T_(2)^4)`

As

`T_(2)=4T_(1)`

Then

`(P_(1) )/(P_(2) ) =(T_(1)^4 )/((4T_(1))^4)`

then

`P_(2)=256*P_(1)`

• The factor will the total energy radiated per second per square meter increase = 256