Question

stion 13 of 20 : Select the best answer for the question. 13. If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C? A. 0.002021624 m3 B. 0.004021624 m3 C. 0.000010812 m3 D. 0.002010812 m3

Answer 1

Answer : The correct option is, (A)
`0.002010812m^3`

Solution : Given,

Volume of mercury at temperature
`20^oC` =
`0.002m^3`

As we know that the mercury is a liquid substance. So, we have to apply the volume of expansion of the liquid.

Formula used for the volume expansion of liquid :

`V_(T)=v_(1)[1+\gamma (T_(2)-T_(1))]`

or,

`V_(2)=V_(1)[1+\gamma (T_(2)-T_(1))]`

where,

`V_(T)` = volume of liquid at temperature
`T^oC`

`V_(1)` = volume of liquid at temperature
`20^oC`

`V_(2)` = volume of liquid at temperature
`50^oC`

`\gamma` = volume expansion coefficient of mercury at
`20^oC` is 0.00018 per centigrade (Standard value)

Now put all the given values in the above formula, we get the volume of mercury at
`50^oC`.

`V_(2)=0.002[1+0.00018(50-20)]=0.0020108m^3`

Therefore, the volume of mercury at
`50^oC` is,
`0.002010812m^3`