Question

What is the binomial expansion of (2x-3)^5

Answer 1

a

Explanation:

Answer 2

(2x)^5 - 15(2x)^4 + 90(2x)^3 - 270(2x)^2 + 405(2x) - 243

first option

Explanation:

Exponent is 5 so the coefficients will be 6

Pascal's triangle

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

So

(2x-3)^5

= 1 (2x)^5 + 5 (2x)^4 (-3) + 10(2x)^3 (-3)^2 + 10(2x)^2 (-3)^3 + 5(2x)(-3)^4 + 1 (-3)^5

= (2x)^5 - 15(2x)^4 + 90(2x)^3 - 270(2x)^2 + 405(2x) - 243