Question

Can someone answer this question? :)

Answer 1

Okay so,

We already have ,

Both circles congruent,
that means their diameter and therefore radius are equal.

Which means,

AM= MB = CN = DN = 148/2 = 74 (radius of congruent Δs)


and

AL = BL = 140/2 = 70 (as a perpendicular on a chord from the center bisects the chord)


InΔ ΑLM and ΔCNQ seem to be congruent,

So,


ML = NQ ( by CPCT)

this means uf you found the value of ML somehow, you'll get the value of NQ.

So by applying pythagoras theorem in ΔALM





`{AL}^(2) + {ML}^(2) = {AM}^(2) \\ \\ {ML}^(2) = {74}^(2) - {70}^(2) = (74 - 70)(74 + 70) \\ \\ {ML}^(2) = (4)(144) \\ ML = √(4 * 144) = 24`




Hence, ML =24 cm =NQ