Question

Parks is wearing several rubber bracelets one third of the bracelets are tie dye 1/6 are blue and 1/3 of the remainder are camouflage if Park swears to camouflage bracelets how many bracelets does he have on

Answer 1

12 bracelets

Explanation:

Given : Parks is wearing several rubber bracelets one third of the bracelets are tie dye 1/6 are blue and 1/3 of the remainder are camouflage

To Find :if Park swears 2 camouflage bracelets how many bracelets does he have on

Solution:

Let x be the number of bracelet are tie dye

Sine we are given that park wears 1/3 of bracelets

Parks is wearing bracelets of tie dye =
`(1)/(3)x`

Parks wearing blue bracelets =
`(1)/(6)x`

So, total bracelets of tie die and blue =
`(1)/(3)x+(1)/(6)x`

=
`(3)/(6)x`

=
`(1)/(2)x`

So, remaining bracelets :

=
`x-(1)/(2)x`

=
`(1)/(2)x`

Since we are given that 1/3 of remaining are camouflage

We are also given that park wears 2 camouflage bracelet

Since we are given that 1/3 of remaining are camouflage

⇒
`(1)/(3) *(1)/(2) x =2`

⇒
`(x)/(6)=2`

⇒
`x=12`

Thus total number of bracelets are 12

Hence he have 12 bracelets