Question

A plot of land is shaped like a quadrilateral. Fences are built on the diagonal to divide the area into 4 sections. What is VI to the nearest tenth?

GV = 6.55

FV = 5.84

VH = 3.27

VI = ?

Answer 1

The vale of VI is 5.3.

To find the length of VI, the diagonal of the quadrilateral, we can use the Pythagorean Theorem. In a quadrilateral with fences built on the diagonal, the sides GV, FV, VH, and VI form a right-angled triangle. Given that GV = 6.55, FV = 5.84, and VH = 3.27, we can apply the Pythagorean Theorem:

VI^2 =GV^2 +VH^2

VI^2 =(6.55)^2 +(3.27)^2

VI^2 =42.9025+10.6929

VI^2 =53.5954

VI≈ 53.5954

VI≈5.32

Rounded to the nearest tenth, VI≈5.3. Therefore, the length of the diagonal VI is approximately 5.3 units.

Answer 2

The value of VI will be= 3.9cm

Explanation:

It is given that A plot of land is shaped like a quadrilateral. Fences are built on the diagonal to divide the area into 4 sections.

Thus, Diagonals bisect each other at V, therefore

GV+VH=VI+VF

Where GV=6.55, FV = 5.84, VH = 3.27, thus

⇒6.55+3.27=VI+5.84

⇒9.82=VI+5.84

⇒9.82-5.84=VI

⇒3.9cm=VI

Thus, the value of VI will be= 3.9cm