Answer: The answer is 50 m³.
Step-by-step explanation: We are given to find the volume of the cone cone after being dilated by a factor of one-third from a cone with volume 1350 m³.
The volume of a cone with base radius 'r' units and height 'h' units is given by

Therefore, if 'r' is the radius of the base of original cone and 'h' is the height, then we can write

Now, if we dilate the cone by a scale factor of
, then the radius and height will become one-third of the original one.
Therefore, the volume of the dilated cone will be

Thus, the volume of the resulting cone will be 50 m³.