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23 votes
For what value of y does 125 =
(1/25)^y-1

User Marc Eaddy
by
7.1k points

1 Answer

4 votes

Answer:


y = -(1)/(2)

Explanation:

I assume that y - 1 is an exponent, and the equation is


125 = ((1)/(25))^(y - 1)


5^3 = (5^(-2))^(y - 1)


5^3 = 5^(-2y + 2)


-2y + 2 = 3


-2y = 1


y = -(1)/(2)

User Aladine
by
7.1k points