Question

How do you create a data set with 8 points in it that has a mean of approximately 10 and a standard deviation of approximately 1?

Answer 1

See below.

Explanation:

The standard deviation = √ (∑(x - 10)^2 / 8 ) must be approximately = 1 if we take the mean to be 10.

This requires ∑ (x - 10)^2 to be approximately equal to 8.

The following data set would fit the bill:

8.6 9 9 10 10 11 11 11.5.

The values of (x - 10)^2 could be 1.96, 1, 1, 0,0, 1, 1, 2.25 = 8.21

This would give a mean of about 10 and standard deviation of about 1.