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What volume of a 2.00 M stock solution of NaOH is needed to prepare 150. mL of 0.40 M solution?

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To find the volume ratios we say m1v1=m2v2

where m1 is the initial molarity, m2 the final molarity, v1 the initial volume, v2 the final volume.in this question m1=2.00M, m2=0.40M v2=150ml

Therefore the expression becomes: 2.00M×v1=0.40M×150mL

v1=(0.40M×150mL)/2.00M

=30mL

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