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The volume of gas a balloon can hold varies directly as the cube of its radius. Imagine a balloon with a radius of 3 inches can hold 81 cubic inches of gas. How many cubic inches of gas must be released to reduce the radius down to 2 inches?

User Flyclassic
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Answer: 57 in³

Explanation:

1. You know that the volume (V) of gas a balloon can hold varies directly as the cube of its radius (r). Then, you can write the following expression:


V=kr^(3)

Where k is the constant of proportionality.

2. You can calculate k as following:


k=(V_1)/(r^(3))\\k=(81in^(3))/((3in)^(3))\\k=3

3. Then, to calculate the cubic inches that must be released to reduce the radius down to 2 inches:

- Solve for the volume as following:


V_2=3(2in)^(3)=24in^(3)

- Make the subtraction of the two volumes shown above. Then, the result is:


V_3=81in^(3)-24in^(3)=57in^(3)

User Kalpit Gajera
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