Question

The base of a triangle is 8 1 3 meters and the height of the triangle is the fourth root of 16 meters meters. What is the area of the triangle?

Answer 1

The area of triangle is
`8 (1)/(3)\ m^(2)`

Explanation:

we know that

The area of a triangle is equal to

A=(1/2)bh

we have

b=8 1/3 m

convert to an improper fraction

8 1/3 m=(8*3+1)/3=25/3 m

The fourth root of 16 is equal to 2

`\sqrt[4]{16}=(2^(4))^(1/4)=2`

so

h=2 m

substitute

`A=(1/2)(25/3)2=25/3\ m^(2)`

convert to mixed number

`25/3=(24/3)+(1/3)=8+1/3=8 (1)/(3)\ m^(2)`