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Solve 3x-18=2y and 5x-6y=6 by elimination PLEASE SHOW WORK !!!!

User Runway
by
8.5k points

2 Answers

2 votes

Answer:

x= 6/5y+6/5

x= 2/3y+6

Explanation:

3x-18=2y

Step 1: Add 18 to both sides.

3x−18+18=2y+18

3x=2y+18

Step 2: Divide both sides by 3.

3x/3= 2y+18/3

x= 2/3y+6

#2

5x−6y=6

Step 1: Add 6y to both sides.

5x−6y+6y=6+6y

5x=6y+6

Step 2: Divide both sides by 5.

5x/5= 6y+6/5

x= 6/5y+6/5



User Idbranding
by
8.9k points
5 votes

Answer:

x =12 and y =9

Explanation:

3x -18 = 2y or 3x -2y = 18

5x-6y = 6

Using elimination method

In order make coefficient of y in both equation same with different sign ,

we multiply equation 1 by -3 and adding the obtained to equation 2

-3(3x-2y) = 18x-3

-9x +6y = -54

5x -6y = 6

-----------------------

-4x = -48

x =
(-48)/(-4) = 12

on plugging the value of y in equation (1) ,we get

3(12) -18 = 2y

36 -18 = 2y

2y = 18

y = 18/2 = 9

x = 12 and y = 9

User Gmetal
by
8.6k points

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