As we know that mass of the iron will remain same in solid state as well as in molten state as per mass conservation theory
Now we can say
![m_(initial) = m_(final)](https://img.qammunity.org/2020/formulas/physics/middle-school/gno8e4yrzjcpqkx3wfu6tti8ylvcep87m9.png)
since mass is the product of volume and density so we can say
![V_i \rho_i = V_(final)\rho_(final)](https://img.qammunity.org/2020/formulas/physics/middle-school/4n0en3xvo3fu2vqg5gvwlhazrigzqnyjb9.png)
now from above equation we have
![(200 cm^3)(7 g/cm^3) = V_(final)(8 g/cm^3)](https://img.qammunity.org/2020/formulas/physics/middle-school/165wf7o263ep98dbu4wqdysruf2vi8cu1a.png)
now by solving above equation we have
![V_(final) = (7)/(8) (200 cm^3)](https://img.qammunity.org/2020/formulas/physics/middle-school/kmeabg98qfghpifb14v0nk3sw8ysrnvafo.png)
![V_(final) = 175 cm^3](https://img.qammunity.org/2020/formulas/physics/middle-school/rdf1ucfd32n3o7oqj2v9g2uihql2iaahm1.png)
so final volume after it get solidify will become 175 cm^3