Question

Determine the number o moles of ions/atoms/particle in the following:

2.50 miles of K2S
(Let me know how to do)

Answer 1

Answer: The number of ions of
`K^+` are
`30.11* 10^(23)` and number of ions of
`S^(2-)` are
`15.055* 10^(23)`.

Step-by-step explanation:

Potassium sulfide,
`K_2S` is an ionic compound. The dissociation of this compound in water will yield:

`K_2S\rightarrow 2K^++S^(2-)`

By Stoichiometry,

One mole of potassium sulfide dissociates into 2 moles of potassium ions and 1 mole of sulfide ion.

According to mole concept:

1 mole of an ionic compound contains
`6.022* 10^(23)` number of ions.

So, 2.5 moles of
`K_2S` will contain
`2.5* 2* 6.022* 10^(23)=30.11* 10^(23)` number of
`K^(+)` ions and
`2.5* 1* 6.022* 10^(23)=15.055* 10^(23)` number of
`S^(2-)` ions.

Hence, the number of ions of
`K^+` are
`30.11* 10^(23)` and number of ions of
`S^(2-)` are
`15.055* 10^(23)`.