Question

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

Answer 1

Guessing it is 3x^2 and 2x^2?

If so
3*3^2-2*5=3*9-10=27-10=17

2*3^2-3*5=2*9-15=18-15=3

Then you do:
17-3=14
So the first equation exceeds the second by 14

Answer 2

14

Explanation:

Put x = 3 and y = 5 to the expressions 3x² - 2y and 2x² - 3y.

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

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3x² - 2y

3 · 3² - 2 · 5 = 3 · 9 - 10 = 27 - 10 = 17

2x² - 3y

2 · 3² - 3 · 5 = 2 · 9 - 15 = 18 - 15 = 3

Make the difference:

17 - 3 = 14