Question

A gas in a balloon at constant pressure has a volume of 160 mL at -125*C. What is its volume at 29.0*C?

Answer 1

Answer:- 330 L

Solution:- At constant pressure, volume is directly proportional to the kelvin temperature.

`V_1T_2=V_2T_1`

where,
`V_1` is the initial volume at initial temperature
`T_1` and
`V_2` is the new volume at temperature
`T_2` .

From given info,

`V_1` = 160 mL

`T_1` = -125 + 273 = 148 K

`T_2` = 29.0 + 273 = 302 K

`V_2` = ?

Let's plug in the values and solve this for new volume.

`160mL(302K)=V_2(148K)`

On rearrangement:

`V_2=(160mL(302K))/(148K)`

[tex]V_2] = 326 L

If we round the answer for two sig figs(as given in initial volume) then it will be 330 L.

So, the new volume of the balloon is 330 L.