Question

The? half-life of a radioactive substance is 20 years. If you start with some amount of this? substance, what fraction will remain in 120 ?years

Answer 1

`\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( (1)/(2) \right)^{(t)/(h)}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\\ t=\textit{elapsed time}\dotfill &120\\ h=\textit{half-life}\dotfill &20 \end{cases} \\\\\\ A=P\left( (1)/(2) \right)^{(120)/(20)}\implies A=P\left( (1)/(2) \right)^6\implies A=P\left( \cfrac{1^6}{2^6} \right)\implies A=\cfrac{1}{64}P`