Question

Write the chemical symbols for three different atoms or atomic cations with 27 electrons. Please help ASAP!

Answer 1

Answer: The chemical symbols for three different atoms or atomic cations with 27 electrons are
`Co,Cu^(2+) \& Ni^(1+)`

Step-by-step explanation:

An atom is neutral specie with equal number of electrons and protons in it.

Atomic number = Number of protons = Number of electrons

Atomic number =- Number electrons = 27

The atom with 27 atomic number Cobalt that Co.

`[Co]=[Ar]3d^74s^2`

A cation is an ionic species which carry positive charge.When an atom looses an electron it forms cation.

Copper has atomic number of 29. When the copper atom looses 2 electrons it get converted into copper cation that is
`Cu^(2+)` with 27 electrons in its ion.

`[Cu]=[Ar]3d^(10)4s^1`

`[Cu^(2+)]=[Ar]3d^(9)4s^0`

Nickel has atomic number of 28.When the nickel atom looses 1 electron it get converted into nickel cation that is
`Ni^(1+)` with 27 electrons in its ion.

`[Ni]=[Ar]3d^(8)4s^2`

`[Ni^(1+)]=[Ar]3d^(8)4s^1`

So,the chemical symbols for three different atoms or atomic cations with 27 electrons are
`Co,Cu^(2+) \& Ni^(1+)`