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What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?
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What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?

User Emallove
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1 Answer

4 votes
PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm



User Napseis
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