Question

1

Which is the equation of a line that has a slope 1/2 and passes through point (2, -3)?
Oy-x-4
0y=x-2
Oy-x+2
Oy=x+3

Answer 1

`y = (1)/(2)x-4`

Explanation:

Equation of line in slope y-intercept form:

`\sf slope = m =(1)/(2)\\\\Point (2, -3) ; x_1 = 2 \ \& y_1 = -3\\\\\boxed{\bf y - y_1 =m(x -x_1)}`

`\sf y - [-3] = (1)/(2)(x - 2)\\\\y + 3 = (1)/(2)x - 2*(1)/(2)\\\\y + 3 = (1)/(2)x-1\\\\`

`\sf y = (1)/(2)x - 1 - 3\\\\ y =(1)/(2)x-4`