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Write 5(6x+4)-2(5x-2) in the form a(bx+c) where a,b and c integers and a>1

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Answer:

4(5x + 6)

Explanation:


5(6x+4)-2(5x-2)\qquad\text{use distributive property}\ a(b+c)=ab+ac\\\\=(5)(6x)+(5)(4)+(-2)(5x)+(-2)(-2)\\\\=30x+20-10x+4\qquad\text{combine like terms}\\\\=(30x-10x)+(20+4)\\\\=20x+24


20x=4\cdot5x\\\\24=4\cdot6\\\\20x+24=4(5x+6)

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