Answer: 12 in. by 10 in.
Explanation:
Given: The dimensions of photo is 10 in. by 8 in.
Therefore, Area of photo=
![10*8=80\ in.^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qp6xkww6d8bes5tnrswwmne49fswcv9b6c.png)
Area of frame with photo=120 square inches
Let x be the width of the frame, then we have
Length of frame with photo= 10+2x inches
Width of frame with photo =8+2x inches
Now,
![(10+2x)(8+2x)=120](https://img.qammunity.org/2020/formulas/mathematics/high-school/fk1k8mnssd954wfj48dvh4bhss5g2jt9ky.png)
![80+16x+20x+4x^2=120\\\Rightarrow\ 4x^2+36x-40=0\\\Rightarrowx^2+9x-10=0\\\(x-1)(x+10)=0\\\Rightarrow\ x=1,...........[text{Since length can not be negative so it cannot be -10}]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/38j28x1vmp9ybk9fcdcsh9myq13lwtpj32.png)
Thus, dimension of frame =
![(10+2(1))(8+2(1))=12\ in.\ by\ 10\ in.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gkcqjhe2t3lj73styr1x4fqy9ufedl7yd6.png)