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How many ordered pairs of positive integers satisfy xY=32?

1 Answer

6 votes

Answer:


Explanation:

xy = 32

x ; y is the divisor of 32

but : 32 = 2^5

6 ordered pairs of positive integers satisfy xY=32

(1;32) , (2;16) , (4; 8),(32; 1) , (16;2) , (8;4) .

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