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WORTH 100 POINTS need the answers asap

first row

-x^2
2x^2
(x/2)^2
x^2

x is less than 2
x is greater than 2
x is less than or equal to 2
x is greater than or equal to 2

second row

-5
-5/2
4
5

•2 is less than x&x is less than 4
•2 is less than or equal to x & x is less than or equal to 4
•2 is less than or equal to x&x is less than 4
•2 is less than x&x is less than or equal to 4

WORTH 100 POINTS need the answers asap first row -x^2 2x^2 (x/2)^2 x^2 x is less than-example-1
User Beinghuman
by
5.4k points

1 Answer

4 votes

Answer:


f(x) = x^2 , x < 2


f(x) = 5, 2\leq x < 4

Explanation:

In the given graph, we have a parabola with a small line near it.

The given parabola goes up to a point where x = 2 but fails to reach that value. Also, x = 2 starts on the line above where x = 2 and ends right before x = 4.

Therefore, the function can be modeled by:


f(x) = x^2 , x < 2


f(x) = 5, 2\leq x < 4

User Igal Serban
by
5.7k points